- Apr 08, 2018 · hybrid state is:sp3d. one lp on each Cr atom 4 pi bonds 2 0- so overall charge is 2-
- sp2 hybridization. The two C−H sigma bonds are formed from overlap of the sp2 hybrid orbitals from carbon with the hydrogen 1s atomic orbitals. The double bond between carbon and oxygen consists of one σ and one π bond. The oxygen atom, like the carbon atom, also has a trigonal planar arrangement of the electrons that requires sp2 ...
- Nov 14, 2018 · Determine the hybridization. Since iodine has a total of 5 bonds and 1 lone pair, the hybridization is sp3d2. The exponents on the subshells should add up to the number of bonds and lone pairs. Fluorine has 1 bond and 3 lone pairs giving a total of 4, making the hybridization: sp3. Adding up the exponents, you get 4.
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